(8x+5)(x^2-2x+2)=0

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Solution for (8x+5)(x^2-2x+2)=0 equation: 


Simplifying
(8x + 5)(x2 + -2x + 2) = 0

Reorder the terms:
(5 + 8x)(x2 + -2x + 2) = 0

Reorder the terms:
(5 + 8x)(2 + -2x + x2) = 0

Multiply (5 + 8x) * (2 + -2x + x2)
(5(2 + -2x + x2) + 8x * (2 + -2x + x2)) = 0
((2 * 5 + -2x * 5 + x2 * 5) + 8x * (2 + -2x + x2)) = 0
((10 + -10x + 5x2) + 8x * (2 + -2x + x2)) = 0
(10 + -10x + 5x2 + (2 * 8x + -2x * 8x + x2 * 8x)) = 0
(10 + -10x + 5x2 + (16x + -16x2 + 8x3)) = 0

Reorder the terms:
(10 + -10x + 16x + 5x2 + -16x2 + 8x3) = 0

Combine like terms: -10x + 16x = 6x
(10 + 6x + 5x2 + -16x2 + 8x3) = 0

Combine like terms: 5x2 + -16x2 = -11x2
(10 + 6x + -11x2 + 8x3) = 0

Solving
10 + 6x + -11x2 + 8x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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